Form a proverb!

Write answers to the following clues. Then pick the first letter of each and form a proverb. If you already know the proverb, it is then easy to solve!

(a) A furnace for making pottery or bricks or lime.
(b) The point exactly opposite to the zenith.
(c) A non-flying bird.
(d) One of the discoverers of the molecular structure of
DNA (Surname),
(e) A unit of illumination.
(f) The apparent path of the Sun in the sky > elative to stars.
(g) The English physicist who is one of the originators of
Quantum Physics (Surname).
(h) The chemical element whose symbol is Au.
(i) The hypothetical medium through which Sight and radio
waves was supposed to travel.
(j) The quantity greate. than any given quantity.
(k) \ 2 is an example of a
(1) A figure with any number of sides and angles,
(m) A sleep-producing drug.
(n) An apparatus found in the laboratory to generate staticelectricity
(Two words),
(o) Young plant before germination,
(p) Half of diameter.

Answer:



Knowledge is Power

(a) Kiln (b) Nadir (c) Ostrich (d) Watson (e) Lux
(f) Elliptic (g) Dirac (h) Gold (i) Ether (j) Infinity
(k) Surd (1) Polygon (m) Opium (n) Wimshurst machine
(0) Embryo (p) Radius

Memory Challenge

As a memory challenge, study the animal silhouettes as follow for two minutes!

Animal Silhouettes

Without looking at the above silhouettes, answer the questions below:

a) How many horses are there?

b) Are there more butterflies than fish?

c) What is the last animal depicted?

d) What is the number of bears?

Answer:

a) 4

b) No

c) Elephant

d) 1

Brain Speed Test

In the following figure, in 15 seconds, can you find which three figures are identical?

Brain Speed Test

Answer:

How much did Alaranthus weigh?

Pymm has many dragons. A few years ago, one of these dragons, Alaranthus, though not fully grown, weighed 1000 pounds plus two-thirds of his own weight. How much did Alaranthus weigh?

Answer:

3000 pounds. Alaranthus's weight was such that 1000 pounds was equal to one-third of his weight. So his total weight in pounds was 3 x 1000.

Stone Stew

After astronaut Mark got to the dig, he collected rock specimens to take back to the Earth scientists. He packed the rocks into three sacks: one for igneous rocks, one for sedimentary and one for metamorphic. But, rushing to return to the aircraft before his portable oxygen ran out, he mislabeled all the sacks. How many rocks did he have to take out of how many sacks in order to find out what was in each one?

Answer:

One rock from one sack. If he were to open the sack labeled "igneous," for instance, and the rock turned out to be sedimentary, then he would know that the other two sacks could not contain sedimentary rocks. The other sacks then would have either igneous or metamorphic rocks in them. Since all the sacks were mislabeled, the one labeled "sedimentary" must then contain metamorphic and the one labeled "metamorphic" must contain igneous rocks.

Which Hexagon

Answer:

C; so that one dot is in both squares and the other dot is in both squares and the circle.

Missing Section

Which section is missing?

Answer:

C: added together, opposite segments contain six empty circles and three with a stripe.

The best comparison

Which of the five makes the best comparison?

YYZZZYZZY is to 221112112 as YYZZYZZY is to:

a) 221221122

b) 22112122

c) 22112112

d) 112212211

e) 212211212



Answer: 

c. Substitute numbers for letters-. Y = 2; Z = 1.

Two words using ten letters

Create two words using the following ten letters each once only.

VODLTAMYSE

Answer:

Vast & Melody

$100 for 100 pens

Your boss has asked you to purchase three different types of ballpoint pen. The first costs 50, the second $5.50, and the third $9.50. He has given you $100 and told you to purchase 100 pens in any combination as long as you spend exactly $100 for 100 pens. Just one solution is possible. Can you find it?

Hint: Familiarity with solving simultaneous equations would be helpful here.

Answer:

It is always helpful to set up a legend of what is given and to work from there.

X = $.50 pens
Y = $5.50 pens
Z = $9.50 pens

Set up two equations as follows:

X + Y + Z = 100
$.50X + $5.50Y + $9.50Z = 100

Now, we need at least one of the values to drop out in order to consider the other two. Multiply the first equation by - .5 to drop X out of both equations.

- 0.5X - 0.5Y - 0.5Z = -50
+ 0.5X + 5.5Y + 9.5Z = 100
__________________________
+ 5.0Y + 9.0Z = 50

5Y = 50 - 9Z
Y = 10 - Z

Since we're dealing with whole numbers, Z must be a whole number and a multiple of 5. In this case, Z can only equal 5. With any greater number, Y will become a negative number. So, Z = 5 and Y becomes 1 leaving X to be 94 pens at $.50.

94 pens at $.50
1 pen at $5.50
5 pens at $9.50

Incorrect View

Here is a cube presented from five different perspectives. One of the views is incorrect. Can you tell which one?

Answer:

View C is not correct.

32 dominoes

The props for this problem are a chessboard and 32 dominoes. Each domino is of such size that it exactly covers two adjacent squares on the board. The 32 dominoes therefore can cover all 64 of the chess-board squares. But now suppose we cut off two squares at diagonally opposite corners of the board and discard one of the dominoes, as shown in Figure 1.3. Is it possible to place the 31 dominoes on the board so that all the remaining squares are covered? If so, show how it can be done. If not, prove it impossible.

Answer:

It is impossible to cover the mutilated chessboard (with two opposite corner squares cut off) with 31 dominoes, and the proof is easy. The two diagonally opposite corners are of the same color. Therefore their removal leaves a board with two more squares of one color than of the other. Each domino covers two squares of opposite color, since only opposite colors are adjacent. After you have covered 60 squares with 30 dominoes, you are left with two uncovered squares of the same color. These two cannot be adjacent, therefore they cannot be covered by the last domino. An interesting question now arises. Suppose that any two squares of opposite color are removed from a chessboard, say squares A and B in Figure 1.14. Can the remaining 62 squares always be completely covered by 31 dominoes? The answer is yes, and Ralph Gomory hit upon a simple, elegant proof. Removing any two squares of opposite color divides the closed path (one square wide) into two segments. Each segment must contain an even number of squares that alternate colors. Obviously each segment can be covered with n dominoes, where n is half the number of squares in the segment. Think of the dominoes as little boxcars that can be placed end to end along each of the two segments. Hence the task is always solvable.

PROSCRIBE

Which word in brackets is most opposite to the word in capitals?

PROSCRIBE [allow, stifle, promote, verify, indict]

Answer:

allow

Form a perfect square!

Which piece, when fitted into the following piece, will form a perfect square?

Answer:

Most opposite in meaning

Which two words are most opposite in meaning?

imaginary, realistic, illegible, impracticable, radical, embellished








Answer:


realistic, impracticable